'''
info = {
"stu1":"Lie","stu2":"Weite","stu3":"Potty"
}
info["stu1"]= "Lee" #修改字典中键-值对
info["stu4"]="Monica" #增加字典
# del info["stu1"] #删除字典,换个方式删除
# info.pop("stu2") #删除,标准删除
# info.popitem() #随机删除

#查找
#info['stu1']
print(info.get('stu11')) #查找,有就返回值,没有就返回None

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print("stu5" in info) #info.has_key("stu5") in py2.x 查找
'''

#字典嵌套 键最好不用中文
China = {
"江苏省":{
"南京市":{"江宁":"A","栖霞":"B","奥体":"C"},
"苏州市":{"吴中":"D","虎丘":"E","阳澄湖":"F"},
"扬州市":{"瘦西湖","东关街","八宝亭"}
},

"浙江省":{
"杭州市":{"西湖":"G","宋城":"H","千岛湖":"I"},
"湖州市":{"莫干山":"J","绍兴":"K"}
}
}

China["浙江省"]["湖州市"]["莫干山"] = '嵌套'
China.setdefault("台湾",{"台北":["Sq","re"]}) #首先找“台湾”这个值,找不到就新建


#update将info更新,重复的值覆盖,没有的键将新增
'''
info = {
"stu1":"Lie","stu2":"Weite","stu3":"Potty"
}
info2 = {2:3,4:5,"stu1":"Alex"}

info.update(info2)
print(info)
c = info.fromkeys([6,7,8],[1,"Test",{"name":"Jack"}]) #初始化新的字典,键为6,7,8,如果没有赋值,值为None
print(c)
c [7][2]["name"] = "Luna" #相当于copy,修改一个值会将字典中所以的值都修改了。三个键共享一个内存地址
print(c)
print(info.items()) #将字典转换成了列表

#print(China)
'''

#字典的循环
info = {
"stu1":"Lie","stu2":"Weite","stu3":"Potty"
}
for i in info: #效率优于下面的方法
print(i,info[i])

for x,y in info.items():
print(x,y)

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