Mysql_案例2:查询出哪些员工的薪资在部门平均薪资之上
案例:查询出哪些员工的薪资在部门平均薪资之上
1、背景:当前数据库有employee表和department表,数据分别如下:
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department表:
SQL 语句:
1 SELECT tt.*,d.name as department_name 2 FROM 3 ( 4 SELECT e.*,t.avgsal 5 from 6 ( 7 SELECT departmentid,AVG(salary) as avgsal 8 from employee 9 GROUP BY departmentid ) t 10 11 INNER JOIN 12 employee as e 13 on 14 t.departmentid=e.departmentid 15 WHERE salary > t.avgsal) tt 16 INNER JOIN 17 department as d 18 on 19 tt.departmentid = d.id;
图例解释:
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