Leetcode 985. Sum of Even Numbers After Queries

简单题,按照它给的说法计算就行.

class Solution:
    def sumEvenAfterQueries(self, A: List[int], queries: List[List[int]]) -> List[int]:
        s = sum(x for x in A if x % 2 == 0)
        ans = []
        for v, i in queries:
            new = A[i] + v
            s += new if new % 2 == 0 else 0
            s -= A[i] if A[i] % 2 == 0 else 0
            ans.append(s)
            A[i] = new
        return ans

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