JavaScript获取URL参数公共方法

佚名 6年前 (2019-04-13) 随笔 1504人围观抢沙发百度已收录

写一个JavaScript获取URL参数的通用方法，可以把它放到常用方法的JS文件中调用，直接上代码例子，新手可以学习一下！

 1 <!DOCTYPE html>
 2 <html lang="en">
 3 <head>
 4     <meta charset="UTF-8">
 5     <meta name="viewport" content="width=device-width, initial-scale=1.0">
 6     <meta http-equiv="X-UA-Compatible" content="ie=edge">
 7     <title>Document</title>
 8     <script>
 9         //获取URL地址参数方法
10         function GetRequest() {
11             var url = location.search;
12             var theRequest = new Object();
13             if (url.indexOf("?") != -1) {
14                 var str = url.substr(1);
15                 strs = str.split("&");
16                 for (var i = 0; i < strs.length; i++) {
17                     theRequest[strs[i].split("=")[0]] = unescape(strs[i].split("=")[1]);
18                 }
19             }
20             return theRequest;
21         }
22 
23         window.onload = function() {
24             //调用方法
25             var Request = new Object();
26             Request = GetRequest();
27             var mapName = decodeURIComponent(Request["MapName"]); //参数名称
28             //输出测试
29             alert(mapName);
30         }
31     </script>
32 </head>
33 <body>
34     
35 </body>
36 </html>