[Swift]LeetCode1025. 除数博弈 | Divisor Game
Alice and Bob take turns playing a game, with Alice starting first.
Initially, there is a number N on the chalkboard. On each player's turn, that player makes a move consisting of:
- Choosing any
xwith0 < x < NandN % x == 0. - Replacing the number
Non the chalkboard withN - x.
Also, if a player cannot make a move, they lose the game.
Return True if and only if Alice wins the game, assuming both players play optimally.
Example 1:
Input: 2
Output: true Explanation: Alice chooses 1, and Bob has no more moves.
Example 2:
Input: 3
Output: false Explanation: Alice chooses 1, Bob chooses 1, and Alice has no more moves.
Note:
1 <= N <= 1000
爱丽丝和鲍勃一起玩游戏,他们轮流行动。爱丽丝先手开局。
最初,黑板上有一个数字 N 。在每个玩家的回合,玩家需要执行以下操作:
- 选出任一
x,满足0 < x < N且N % x == 0。 - 用
N - x替换黑板上的数字N。
如果玩家无法执行这些操作,就会输掉游戏。
只有在爱丽丝在游戏中取得胜利时才返回 True,否则返回 false。假设两个玩家都以最佳状态参与游戏。
示例 1:
输入:2 输出:true 解释:爱丽丝选择 1,鲍勃无法进行操作。
示例 2:
输入:3 输出:false 解释:爱丽丝选择 1,鲍勃也选择 1,然后爱丽丝无法进行操作。
提示:
1 <= N <= 1000
1 class Solution { 2 func divisorGame(_ N: Int) -> Bool { 3 return N % 2 == 0 4 } 5 }
Runtime: 4 ms
Memory Usage: 18.6 MB1 class Solution { 2 func divisorGame(_ N: Int) -> Bool { 3 var N = N 4 var alice:Bool = false 5 for x in 1..<N 6 { 7 alice.toggle() 8 if N % x == 0 9 { 10 N -= x 11 } 12 } 13 return alice 14 } 15 }
更多精彩

