(二叉树 BFS) leetcode 111. Minimum Depth of Binary Tree

佚名 6年前 (2019-04-16) 随笔 322人围观抢沙发百度已收录

Given a binary tree, find its minimum depth.

The minimum depth is the number of nodes along the shortest path from the root node down to the nearest leaf node.

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Note: A leaf is a node with no children.

Example:

Given binary tree [3,9,20,null,null,15,7],

return its minimum depth = 2.

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求二叉树的最小深度，嗯，这个题可以用DFS，也可以用BFS，我这个题先用BFS写。

C++代码：

/**
 * Definition for a binary tree node.
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 * };
 */
class Solution {
public:
    int minDepth(TreeNode* root) {
        queue<TreeNode*> q;
        if(!root)
            return 0;
        q.push(root);
        int sum = 0;
        while(!q.empty()){
            sum++;
            for(int i = q.size(); i > 0; i--){  //必须写循环，如果不写，对于[1,2,3,4,5]，将会返回3，与题目要求不符。
                auto t = q.front();
                q.pop();
                if(!t->left &&!t->right) return sum;
                if(t->left) q.push(t->left);
                if(t->right) q.push(t->right);
            }
        }
        return 0;
    }
};