Python: Enum枚举的实现
如果是新版Python用户(Python 3.4 with PEP 435):
?1 2 | from enum import Enum Animal = Enum( 'Animal' , 'ant bee cat dog' ) |
SRE实战 互联网时代守护先锋,助力企业售后服务体系运筹帷幄!一键直达领取阿里云限量特价优惠。
or
?1 2 3 4 5 | class Animals(Enum): ant = 1 bee = 2 cat = 3 dog = 4 |
旧版Python用户可以充分发挥动态语言的优越性来构造枚举,有简单的:
?1 2 3 4 5 | def enum( * * enums): return type ( 'Enum' , (), enums) Numbers = enum(ONE = 1 , TWO = 2 , THREE = 'three' ) # Numbers.ONE == 1, Numbers.TWO == 2 and Numbers.THREE == 'three' |
有复杂的:
?1 2 3 4 5 6 | def enum( * sequential, * * named): enums = dict ( zip (sequential, range ( len (sequential))), * * named) return type ( 'Enum' , (), enums) Numbers = enum( 'ZERO' , 'ONE' , 'TWO' ) # Numbers.ZERO == 0 and Numbers.ONE == 1 |
有带值到名称映射的:
?1 2 3 4 5 6 7 | def enum( * sequential, * * named): enums = dict ( zip (sequential, range ( len (sequential))), * * named) reverse = dict ((value, key) for key, value in enums.iteritems()) enums[ 'reverse_mapping' ] = reverse return type ( 'Enum' , (), enums) # Numbers.reverse_mapping['three'] == 'THREE' |
有用set实现的:
?1 2 3 4 5 6 7 8 | class Enum( set ): def __getattr__( self , name): if name in self : return name raise AttributeError Animals = Enum([ "DOG" , "CAT" , "HORSE" ]) print Animals.DOG |
有用range实现的:
?1 2 3 4 5 6 7 | dog, cat, rabbit = range ( 3 ) # or class Stationary: (Pen, Pencil, Eraser) = range ( 0 , 3 ) print Stationary.Pen |
原文:http://www.cnblogs.com/codingmylife/archive/2013/05/31/3110656.html
有用tuple实现的:
?1 2 3 4 | class Enum( tuple ): __getattr__ = tuple .index State = Enum([ 'Unclaimed' , 'Claimed' ]) print State.Claimed |
有用namedtuple实现的:
?1 2 3 4 5 6 7 8 9 10 11 12 13 14 | from collections import namedtuple def enum( * keys): return namedtuple( 'Enum' , keys)( * keys) MyEnum = enum( 'FOO' , 'BAR' , 'BAZ' ) # 带字符数字映射的,像C/C++ def enum( * keys): return namedtuple( 'Enum' , keys)( * range ( len (keys))) # 带字典映射的,可以映射出各种类型,不局限于数字 def enum( * * kwargs): return namedtuple( 'Enum' , kwargs.keys())( * kwargs.values()) |

更多精彩