A+B Format

佚名 6年前 (2019-04-24) 随笔 631人围观抢沙发百度已收录

Calcuate a + b and ouput the sum in standard format - that is, the digits must be separated into groups of three by commas(unless there are less than four digits).

Input: Each input file contains one test case.Each case contains a pair of integers a and b where -1000000 <= a, b <= 1000000. The numbers are separated by a space.

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Output: For each test case, you should output the sum of a and b in one line. The sum must be written in the standard format.

Sample Input:

-1000000 9

Sample Output

-999,991

分析：在输出下标i的数字后，考虑((i+1)%3 == len % 3 && i != len - 1)是否成立，若成立就加上一个句号

代码：

 1 #include <cstdio>
 2 
 3 int main(){
 4     int a, b;
 5     scanf("%d%d", &a, &b);
 6     int sum = a + b;
 7     if(sum < 0){
 8         printf("-");
 9         sum = 0 - sum;
10     }
11     int num[10];
12     int len = 0;
13     if(sum == 0) printf("0");
14     while(sum){
15         num[len++] = sum % 10;
16         sum /= 10;
17     }
18     
19     for(int i = 0; i < len / 2; i++){
20         int temp = num[i];
21         num[i] = num[len-i-1];
22         num[len-i-1] = temp;
23     }
24     
25     for(int i = 0; i < len; i++){
26         printf("%d", num[i]);
27         if((i+1)%3 == len%3 && i != len-1){
28             printf(",");
29         }
30     }
31     return 0;
32 }