dp回文

佚名 6年前 (2019-04-25) 随笔 1628人围观抢沙发百度已收录

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 1 #include<iostream>
 2 #include<algorithm>
 3 #include<string>
 4 using namespace std;
 5 int dp[100][100] = { 0 };
 6 int main(void)
 7 {
 8     string s1;
 9     while (cin >> s1)
10     {
11         int length = s1.length();
12         int i;
13         for (i = 0; i <= length - 1; ++i)
14             dp[i][i] = 1;
15         int j;
16         for (i = length-1; i >=0; --i)
17         {
18             for (j = i+1; j <=length-1; ++j)
19             {
20                 if (s1[i] == s1[j])
21                 {
22                     dp[i][j] = dp[i + 1][j - 1] + 2;
23                 }
24                 else
25                 {
26                     dp[i][j] = max(dp[i + 1][j], dp[i][j - 1]);
27                 }
28             }
29         }
30         cout << "最长回文子序列的长度是"<<dp[0][length - 1] << endl;
31     }
32     return 0;
33 }

 1 #include<iostream>
 2 #include<algorithm>
 3 #include<string>
 4 using namespace std;
 5 int dp[100][100] = { 0 };
 6 int main(void)
 7 {
 8     string s1;
 9     while (cin >> s1)
10     {
11         int length = s1.length();
12         int i;
13         for (i = 0; i <= length - 1; ++i)
14             dp[i][i] = 1;
15         int j;
16         for (i = length - 1; i >= 0; --i)
17         {
18             for (j = i + 1; j <= length - 1; ++j)
19             {
20                 if (s1[i] != s1[j])
21                 {
22                     dp[i][j] = dp[i + 1][j] + dp[i][j - 1] - dp[i + 1][j - 1];
23                 }
24                 else
25                 {
26                     dp[i][j] = dp[i + 1][j] + dp[i][j - 1] - dp[i + 1][j - 1] + dp[i + 1][j - 1] + 1;
27                 }
28             }
29         }
30         cout << "回文子序列的个数是"<<dp[0][length - 1] << endl;
31     }
32     return 0;
33 }

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 1 #include<iostream>
 2 #include<algorithm>
 3 #include<string>
 4 using namespace std;
 5 int dp[100];           //长度
 6 bool ispalindrome(string s,int start,int end)
 7 {
 8     while (start <= end)
 9     {
10         if (s[start] != s[end])
11         {
12             return false;
13         }
14         ++start;
15         --end;
16     }
17     return true;
18 }
19 int main(void)
20 {
21     string s;
22     while (cin >> s)
23     {
24         int length = s.length();
25         int i;
26         for (i = 0; i <= length; ++i)
27         {
28             dp[i] = i - 1;
29             if (ispalindrome(s, 0, i-1) == true)
30             {
31                 dp[i] = 0;
32             }
33         }
34         int j;
35         for (i = 0; i <= length-1; ++i)
36         {
37             for (j = 0; j <= i; ++j)
38             {
39                 if (ispalindrome(s, j, i) == true)
40                 {
41                     dp[i + 1] = min(dp[i + 1], dp[j] + 1);
42                 }
43             }
44         }
45         cout << "需要分割的次数为" << dp[length] << "次"<<endl;
46     }
47     return 0;
48 }