python--批量修改文件夹名

佚名 6年前 (2019-05-07) 随笔 2043人围观抢沙发百度已收录

python代码如下：

import os , re
import os.path

rootdir = r'C:\Users\Administrator\Desktop\222'
# rootdir = os.path.abspath(rootdir)

print('absolute root path:\n*** ' + rootdir + ' ***')
# 先修改文件名,循环文件夹和子文件夹，文件名
for dirname, subdir, filenames in os.walk(rootdir):
   for filename in filenames:
      pathfile = os.path.join(dirname, filename)
      euroFilename = re.search(r'([a-zA-Z]+)(-|$)?([a-zA-Z]+)',filename)
      mvfile = euroFilename.group() + '.yml'
      mvpathfile = os.path.join(dirname,mvfile)
      if 'shtel' in filename:
         continue
      elif 'gateway' in filename:
         continue
      os.rename(pathfile, mvpathfile)
#在改文件夹名
for parent, dirnames, filenames in os.walk(rootdir, topdown=False):
   for dirname in dirnames:
      pathdir = os.path.join(parent, dirname)
      euroFilename = re.search(r"(\bstage\b)?-?([a-zA-Z1]+)(-[a-zA-Z1]+)?(-conf)?(-master)?", dirname)
      mvpathdir = os.path.join(parent, euroFilename.group())
      os.rename(pathdir, mvpathdir)
      pathname = [euroFilename.group(2), euroFilename.group(3), euroFilename.group(5)]
      if pathname[1] == None:
         continue
      pathdirs = ''.join(pathname)
      pathnames = os.path.join(parent, pathdirs)
      os.rename(mvpathdir, pathnames)     #去掉文件夹的stage字段